X^2+25x-2459=0

Solution for X^2+25x-2459=0 equation:

X^2+25X-2459=0

a = 1; b = 25; c = -2459;
Δ = b2-4ac
Δ = 252-4·1·(-2459)
Δ = 10461
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{10461}}{2*1}=\frac{-25-\sqrt{10461}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{10461}}{2*1}=\frac{-25+\sqrt{10461}}{2}
$